| Category: utilities | Component type: concept |
| X | A type that is a model of Assignable |
| x, y | Object of type X |
| Name | Expression | Type requirements | Return type |
|---|---|---|---|
| Copy constructor | X(x) | X | |
| Copy constructor |
X x(y); X x = y; |
||
| Assignment | x = y [1] | X& | |
| Swap | swap(x,y) | void |
| Name | Expression | Precondition | Semantics | Postcondition |
|---|---|---|---|---|
| Copy constructor | X(x) | X(x) is a copy of x [2] | ||
| Copy constructor | X(x) | X(x) is a copy of x [2] | ||
| Copy constructor |
X x(y); X x = y; |
x is a copy of y [2] | ||
| Assignment | x = y [1] | x is a copy of y [2] | ||
| Swap | swap(x,y) |
Equivalent to
{
X tmp = x;
x = y;
y = tmp;
}
|
[1] One implication of this requirement is that a const type is not Assignable. For example, const int is not Assignable: if x is declared to be of type const int, then x = 7 is illegal. Similarly, the type pair<const int, int> is not Assignable.
[2] The reason this says "x is a copy of y", rather than "x == y", is that operator== is not necessarily defined: equality is not a requirement of Assignable. If the type X is EqualityComparable as well as Assignable, then a copy of x should compare equal to x.
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